Material Name End Areas Unadjusted Adjusted Mult Mass Station Volumes Volumes Factor Ordinate (square (cubic (cubic meters) meters) meters) ----------- ---------------- ---------- ---------- ---------- ------ -------- 12+740.00 ITEM_NO._20401__ROADWAY_EXCAVATION Common Exc 0.55(shown) 32 32 1.00 Subgrade Exc 0.01(shown) 1 1 1.00 Subsoil Exc 0.00 0 0 1.00 Fill 0.00 0 0 1.00 13592 TOPSOIL Common Exc 0.70 (shown) 7 7 1.00 Subgrade Exc 0.06 (shown) 1 1 1.00 Subsoil Exc 0.92 (see rt) 9 9 1.00.............. 0.11 Fill 0.00 0 0 1.00 13592 0.47 Mass ordinate for TOPSOIL = 17 0.34 EX_PAVE TOTAL=0.92 Common Exc 0.00 0 0 1.00 Subgrade Exc 0.10 (shown) 1 1 1.00 Subsoil Exc 0.41 (shown) 4 4 1.00 Fill 0.00 0 0 1.00 13592 Mass ordinate for EX_PAVE = 5 SUITABLE Common Exc 0.00 0 0 1.00 Subgrade Exc 0.00 0 0 1.00 Subsoil Exc 0.00 0 0 1.00 Fill 1.83(see rt) 25 25 1.00 13567.......0.11 ITEM_NO._40101__HOT_ACP 0.11 Common Exc 0.00 0 0 0.00 0.47 Subgrade Exc 0.00 0 0 0.00 0.41 Subsoil Exc 0.00 0 0 0.00 0.34 Fill 0.54 11 0 0.00 13567 0.39 ITEM_NO._30201__EMULSIFIED_BASE_GR_D TOTAL = 1.83 Common Exc 0.00 0 0 0.00 Subgrade Exc 0.00 0 0 0.00 Subsoil Exc 0.00 0 0 0.00 Fill 0.43 9 0 0.00 13567 ITEM_NO._30101__AGGREGATE_BASE_GR_D Common Exc 0.00 0 0 0.00 Subgrade Exc 0.00 0 0 0.00 Subsoil Exc 0.00 0 0 0.00 Fill 1.10 22 0 0.00 13567 ITEM_NO._20407_SELECT_TOPPING Common Exc 0.00 0 0 0.00 Subgrade Exc 0.00 0 0 0.00 Subsoil Exc 0.00 0 0 0.00 Fill 2.33 47 0 0.00 13567
The example shown above is a typical cross section, with four pavement layers. In this example, additional lines have been drawn illustrating the existing pavement and existing topsoil to be removed.
These additional lines can be drawn automatically using criteria. Several files are required:
Within the Prxs_m10.inp file is a define statement that reads, "maximum existing road with" and a value. This tells the software how far apart to search for the elements that represent the existing edge of pavement. This is necessary for situations where frontage roads are also present in the file. An example of the user defined variables are shown below:
define_dgn "edge existing pavement" \
dgn = Planview.dgn lv=3 co=3
define "maximum existing road width" 15
define "topsoil depth" 0.10
define "exist pavement thickness" 0.12
define "rock depth" 0
As shown above... a rock layer may also be drawn if desired.
An example of the earthwork input file and the areas for consideration as shown in blue below:
NOTE: "Excavation Limits" must be present in the XS file for the quantities to be calculated by the earthwork input file. The topsoil will be excavated (and backfilled in embankment areas) up to the Excavation Limits lines.
XSECTION Earthwork tolerance = 0.001 xs dgn = ew_test.dgn Existing Ground Line soil type = Item_No._20401__ROADWAY_EXCAVATION roadway exc mult factor = 1.00 subsoil exc mult factor = 1.00 fill mult factor = 1.00 type = line lv = 56 co = 0 Existing Suitable Material soil type = rock roadway exc mult factor = 1.10 subsoil exc mult factor = 1.10 fill mult factor = 1.00 type = line lv = 57 co = 57 Existing Unsuitable Material soil type = topsoil roadway exc mult factor = 1.00 subsoil exc mult factor = 1.00 fill mult factor = 1.00 type = line lv = 57 co = 2 Existing Unsuitable Material soil type = ex_pave roadway exc mult factor = 1.00 subsoil exc mult factor = 1.00 fill mult factor = 1.00 type = line lv = 57 co = 3 Existing Suitable Material soil type = Item_No._20401__ROADWAY_EXCAVATION roadway exc mult factor = 1.0 subsoil exc mult factor = 1.0 fill mult factor = 1.00 type = line lv = 54 co = 54 Existing Unsuitable Material soil type = Item_No._20402__SUBEXCAVATION roadway exc mult factor = 1.0 subsoil exc mult factor = 1.0 fill mult factor = 1.00 type = line lv = 58 co = 58 Existing Unsuitable Material soil type = ex_pave1 roadway exc mult factor = 1.00 subsoil exc mult factor = 1.00 fill mult factor = 1.00 type = line lv = 45 co = 0 Existing Unsuitable Material soil type = ex_pave2 roadway exc mult factor = 1.00 subsoil exc mult factor = 1.00 fill mult factor = 0.00 type = line lv = 46 co = 3 Existing Unsuitable Material soil type = Item_No._20801__STRUCTURE_EXCAVATION roadway exc mult factor = 1.00 subsoil exc mult factor = 1.00 fill mult factor = 1.00 type = line lv = 55 co = 55 /* added lv = 46 & co = 3 */ Proposed Finish Grade soil type = Suitable roadway exc mult factor = 1.00 subsoil exc mult factor = 1.00 fill mult factor = 1.00 type = line lv = 2,8,10,46 co = 0,10-11,16-17,244,3 Proposed Undercut soil type = Item_No._40101__HOT_ACP roadway exc mult factor = 0.000001 subsoil exc mult factor = 0.000001 fill mult factor = 0.000001 type = line lv = 3 co = 3 Proposed Undercut soil type = Item_No._30201__EMULSIFIED_BASE_GR_D roadway exc mult factor = 0.000001 subsoil exc mult factor = 0.000001 fill mult factor = 0.000001 type = line lv = 4 co = 4 Proposed Undercut soil type = Item_No._30101__AGGREGATE_BASE_GR_D roadway exc mult factor = 0.000001 subsoil exc mult factor = 0.000001 fill mult factor = 0.000001 type = line lv = 5 co = 5 Proposed Undercut soil type = Item_No._20407_SELECT_TOPPING roadway exc mult factor = 0.000001 subsoil exc mult factor = 0.000001 fill mult factor = 0.000001 type = line lv = 6 co = 6 Proposed Undercut soil type = FOUNDATION_FILL roadway exc mult factor = 0.000001 subsoil exc mult factor = 0.000001 fill mult factor = 0.000001 type = line lv = 7 co = 7 Proposed Undercut soil type = Item_No._25103__KEYED_RIPRAP roadway exc mult factor = 0.000001 subsoil exc mult factor = 0.000001 fill mult factor = 0.000001 type = line lv = 9 co = 9 Proposed Undercut soil type = Suitable roadway exc mult factor = 0.000001 subsoil exc mult factor = 0.000001 fill mult factor = 1.0 type = line lv = 11 co = 11 /*Proposed Undercut common excavation only soil type = select_borrow roadway exc mult factor = 1.00 subsoil exc mult factor = 1.00 fill mult factor = 1.10 type = line lv = 59 co = 59 */ Excavation Limits type = line lv = 43 co = 0 Write Earthwork Shapes plot param lv = 52 co = 0 wt = 0 lc = 0 Stratify Shape Color /* combine common exc + subgrade exc + subsoil exc */ Process Earthwork for Baseline = a job number = 123 beg sta = 12+760 end sta = 12+760Back to EARTHWORK